JavaScript代码判断输入的字符串是否含有特殊字符和表情代码实例

代码如下：

reg = /[~#^$@%&!?%*]/gi;
if (reg.test(postdata.Name.trim())) {
alert("姓名不能含有特殊字符");
} else {
if (isEmojiCharacter(postdata.Name.trim())) {
alert("姓名不能含有表情");
} else {
//自己的代码
}
}
function isEmojiCharacter(substring) {
for (var i = 0; i < substring.length; i++) {
var hs = substring.charCodeAt(i);
if (0xd800 <= hs && hs <= 0xdbff) {
if (substring.length > 1) {
var ls = substring.charCodeAt(i + 1);
var uc = ((hs - 0xd800) * 0x400) + (ls - 0xdc00) + 0x10000;
if (0x1d000 <= uc && uc <= 0x1f77f) {
return true;
}
}
} else if (substring.length > 1) {
var ls = substring.charCodeAt(i + 1);
if (ls == 0x20e3) {
return true;
}
} else {
if (0x2100 <= hs && hs <= 0x27ff) {
return true;
} else if (0x2B05 <= hs && hs <= 0x2b07) {
return true;
} else if (0x2934 <= hs && hs <= 0x2935) {
return true;
} else if (0x3297 <= hs && hs <= 0x3299) {
return true;
} else if (hs == 0xa9 || hs == 0xae || hs == 0x303d || hs == 0x3030
|| hs == 0x2b55 || hs == 0x2b1c || hs == 0x2b1b
|| hs == 0x2b50) {
return true;
}
}
}
}